Re: "auto" operators syntax
ThosRTanner wrote:
Andrei Polushin wrote:
class A {
int first;
int second;
public:
A(int first, int second) auto;
/*
: first(first), second(second) {}
*/
Well, I can sort of see this, but I write very few classes where the
only private data members are those initialised by the constructor.
I didn't mean /private/, but /any/ members, listed in declaration order
as constructor parameters, to be assigned to respective members.
There's probably some sort of argument for just having
A(...) auto; // Equivalent to a(int first_, int second_) :
// first(first_), second(second_)
This seems to be more error-prone in case when we'll add third member.
And it's hard for documentation tool.
A& operator+=(const A& a) auto;
/*
first += a.first;
second += a.second;
return *this;
*/
This is not necessarily an intuitive implementation - OK for complex,
but for other things?
Well, agreed here: it's contradictious. Should we allow only
operator+() to be auto, but require user to provide operator+=()
explicitly? This is the way of C# (but in reverse order).
You should have also listed all the standard arithmetic operators.
<snip>
A& operator++() auto;
/*
++first;
++second;
return *this;
*/
I cannot believe this to be the case for any class with more than one
data member. I think A& operator++() { *this += 1; return *this } might
be more useful.
It seems to be more correct, thank you.
bool operator<(const A& a) const auto;
/*
return first < a.first
|| first == a.first && second < a.second
;
*/
Umm. This doesn't seem to be compatible with your ++.
But it's OK with your correction.
Anyway, IIRC, there are some templates in boost that allow you to do
that sort of thing.
Yes, and those templates are "curiously recurring", which is neither
simple nor safe pattern - would you recommend them for novices?
Anyway, I can do it manually.
--
Andrei Polushin
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