Re: Returning Refs
"Victor Bazarov" <v.Abazarov@comAcast.net> wrote in message
news:yvqdnS_pT4j-WJLbnZ2dnUVZ_v6tnZ2d@comcast.com...
Jim Langston wrote:
<EvilOldGit@googlemail.com> wrote in message
news:1175349463.536538.36070@y80g2000hsf.googlegroups.com...
const Thing &operator++(int)
{
Thing temp = *this;
operator++();
return temp;
}
Is this code robust ?
No. You are returning a reference to a temporary item.
Just a clarification here... 'Temporary' has a very specific
meaning in C++. 'temp' here is an *automatic* object, and not
a C++ temporary. While it *is* temporary (hell, the whole
program is temporary since it only lasts while in computer's
memory), it has different lifetime than a _true temporary_.
Yes, I guess You are returning a reference to an automatic variable that is
only temporary, it gets destroyed with then method returns. would help
clarify. I have to remember not to use temporary to mean temporary in
duration when it could be confused with C++'s temporary objects.
temp gets
destroyed when this mothod returns and so your'e returning a
reference to something that no longer exists.
[..]
I have no problem with the rest of your assessment.
V
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