Re: Stream state question

From:
"Alf P. Steinbach" <alfps@start.no>
Newsgroups:
comp.lang.c++
Date:
Tue, 02 Oct 2007 10:34:41 +0200
Message-ID:
<13g40l4uhn8fc5@corp.supernews.com>
* Alf P. Steinbach:

* James Kanze:

On Oct 1, 10:51 am, john <j...@no.spam> wrote:

James Kanze wrote:

Why isn't operator bool() used instead? For historical
reasons?


The most obvious reason is that iostream was part of the
language before bool was. And that bool is an integral type,
which can lead to unexpected results when used with the >> and
<< operators.


basic_osstream has explicit "operator<<()" definitions for both "bool"
and "const void *".


Not with those types on the right hand side. The problem is
that given something like "std::cout << myType", where myType
converts implicitly to an integral type, if the implicit
conversion were to bool (and not void*) the compiler will find a
match even if the user has forgotten to declare the desired <<
operator. This is not true for void*.


#include <iostream>
#include <ostream>

int main()
{
    using namespace std;
    cout << cout << std::endl;
}


Oh, sorry, now I see you mention that case later.

But that means that I fail to understand what you mean above.

E.g.

#include <iostream>
#include <ostream>

struct S{ operator void*() const { return 0; } };

int main()
{
     using namespace std;
     cout << S() << std::endl;
}

must compile fine with any standard-conforming compiler.

Cheers,

- Alf

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