Re: More on 'smart pointers'

From:
 James Kanze <james.kanze@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Fri, 09 Nov 2007 10:05:16 -0000
Message-ID:
<1194602716.194853.100840@57g2000hsv.googlegroups.com>
On Nov 8, 5:15 pm, Keith Willis <m...@privacy.net> wrote:

Moving along from my experiments with auto_ptr, I threw
together a custom smart pointer template based on stuff I saw
at the GOTW site. It all works swimmingly, except when I need
to pass the underlying pointer to a function like memset() or
whatever. The template has overloads for operator->() and
operator*() like this:

template <class T> class SmartPtr
{
<snip>
        T& operator*() const
        { return *p_; }

        T* operator->() const
        { return p_; }
<snip>
}

This is fine and I can access members using the normal
p_->member syntax. But what about when I want to pass the
pointer to a function, like this:

        memset(p_, value, sizeof *p_);

This gives me an error complaining that it can't convert a
SmartPtr<whatever> to a void*. At present I've worked around
it by adding a method to the template which explicitly returns
the address:

template <class T> class SmartPtr
{
<snip>
        T& operator*() const
        { return *p_; }

        T* operator->() const
        { return p_; }

        T* Addr() const
        { return p_; }
<snip>
}

which lets me do:

        memset(p_.Addr(), value, sizeof *p_);

Is this the only/best way around the problem?


That's the usual solution (although I can't think of a case
where I'd want to memset something that was managed by a smart
pointer).

--
James Kanze (GABI Software) email:james.kanze@gmail.com
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