Re: Bjarne's exception safe sample

From:
"Daniel T." <daniel_t@earthlink.net>
Newsgroups:
comp.lang.c++
Date:
Sun, 23 Dec 2007 08:36:28 -0500
Message-ID:
<daniel_t-0D57E5.08362823122007@earthlink.vsrv-sjc.supernews.net>
In article
<9f86e74b-8bab-4da7-afff-36bf1f39438b@s19g2000prg.googlegroups.com>,
 George2 <george4academic@yahoo.com> wrote:

Hello everyone,

Here is Bjarne's exception safe sample,

http://www.research.att.com/~bs/3rd_safe.pdf

[Code]
template <class T> class Safe {

T* p ; // p points to a T allocated using new
public :
Safe () :p (new T ) { }
~Safe () { delete p ; }
Safe & operator =(const Safe & a) { *p = *a .p ; return *this; }
/ / ...
};
template <class T> class Unsafe { // sloppy and dangerous code
T* p ; // p points to a T
public :
Unsafe (T* pp ) :p (pp ) { }
~Unsafe () { if (!p ->destructible ()) throw E(); delete p; }
Unsafe & operator =(const Unsafe & a)
{
p ->~T (); // destroy old value (?10.4.11)
new (p) T (a .p ); // construct copy of a.p in *p (?10.4.11)
return *this;
}
/ / ...
};
[/Code]

What makes me confused is, the description about why it is not
exception safe,

--------------------
The assignment operator may fail by throwing an exception from T 's
copy constructor. This would
leave a T in an undefined state because the old value of *p was
destroyed and no new value
replaced it.
--------------------

In my study, I can not find a case why there is exception thrown from
Unsafe's copy constructor. Any ideas?


Not Unsafe's copy constructor, but T's copy constructor. If during the
call to Unsafe's op=, T's copy constructor throws an exception, the
object that Unsafe points to will be in an indeterminate state.

(Just as a BTW, neither class above is really safe because they are both
missing appropriate copy constructors.)

BTW: it is also appreciated if you could share some experiences about
what in your minds does invariant status mean

(in Bjarne's minds, exception safety means making the object into
invariant status). I find the word *invariant* is
somethings hard to understand. :-)


An invariant of a class is something that is always true about all
objects of that class. One of Safe's invariants is that it always points
to a valid T. Unsafe can't make that claim.

You might want to read (http://citeseer.ist.psu.edu/227598.html) as well.

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