Re: i++ or ++i ?

From:
"Daniel T." <daniel_t@earthlink.net>
Newsgroups:
comp.lang.c++
Date:
Fri, 08 Feb 2008 14:39:57 -0500
Message-ID:
<daniel_t-FBCFBB.14395708022008@earthlink.vsrv-sjc.supernews.net>
"John Brawley" <jgbrawley@charter.net> wrote:

Please pardon a maybe very stupid question?
I've read and reread Bjarne Stroustrup on this, and I still don't "get it,"
so I wrote this to help me understand, and now I _really_ don't "get it."
Why, if one increments before, and the other after, do these snippets output
exactly the same?

#include <iostream>

int main() {
for(int i=0; i<10; i++)
std::cout<<i<<", ";
std::cout<<"\n";
for(int i=0;i<10;++i)
std::cout<<i<<", ";
std::cout<<"\n";
int b=7;
b++; std::cout<<b;
int c=7;
++c; std::cout<<"\n"<<c;
//????????? why? same outputs!
return 0;
}

_Same_output_.
What's the difference?
(I use these in a program, which doesn't crash....)


And lastly, this may help. When overloading the two operators, the
canonical implementations are:

class T {
public:
   //prefix operator
   T& operator++() {
      // increment this
      return *this;
   }

   //postfix operator
   T operator++(int) {
      T tmp( *this );
      // increment this
      return tmp;
   }
};

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