Re: assignment operator and const members

From:
"Bo Persson" <bop@gmb.dk>
Newsgroups:
comp.lang.c++.moderated
Date:
Sun, 23 Nov 2008 03:16:51 CST
Message-ID:
<6oqavjF4tv4kU1@mid.individual.net>
Boris Rasin wrote:

On Nov 21, 9:58 pm, Jonathan Jones <clcppm-pos...@this.is.invalid>
wrote:

I guess the problem that lead to my original question (wanting
assignment to work with const members), is that C++ doesn't fully
support it. What I _really_ want is this:

struct Object
{
    Object(int data, ...) : data_(data), ... {}
    Object(const Object& r) : data_(r.data_), ... {}

    foo() { ... } // can modify everything except data_
    bar() { ... } // can modify everything except data_
    baz() { ... } // can modify everything except data_

    Object& operator=(const Object& r) { data_=r.data; ... }

private:
    const int data_;
    // lots of non-const data

};

I know you could const-qualify all the member functions, while
declaring all the other data as mutable, but that seems ugly at
best.


Interesting idea. Perhaps utilizing keyword mutable to specify that
member function can change const data members:

struct Object
{
   foo() { ... } // can modify everything except data
   bar() const { ... } // can't modify anything
   baz() mutable { ... } // can modify everything including data

   Object& operator=(const Object& r) mutable { data=r.data; ... }

   const int data;
};

This also provides information compiler needs to keep optimizing
const data access when possible, but also know when it needs to
reload const values (after call to any mutable member function).


A nice idea at first, but what if I want baz() do modify data1, and
bar() to modify data2, but not vice versa? :-)

I think the solution to the original problem is to store the data
member in its own class, and have that class' interface manage the
access rules.

Bo Persson

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