Re: basic_ostream, wchar_t * and implicit conversions

Hello

I have a class MyString defining a type conversion operator.
In this first case, when the type conversion converts MyString to an
int, the output is "1", as expected.
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#include <iostream>

struct MyString{
operator const int() const{
return 1;
}
};

int main (void) {
MyString str;

std::wcout << str; //outputs "1"
std::wcout << 1; //outputs "1"

return 0;
}
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In this case instead when converting implicitly to a const wchar_t
*, it outputs its memory address, instead of "Hello".
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#include <iostream>

struct MyString{
operator const wchar_t *() const{
return L"Hello";
}
};

int main (void) {
MyString str;

std::wcout << str; // outputs a memory address
std::wcout << L"Hello"; // outputs "Hello"

return 0;
}
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This happens because in std::basic_ostream there is an
operator<<(int),
and an operator<<(void const *) but there is no operator<<(wchar_t
const *).

When you pass directly a wchar_t const *, that is correctly handled
by the template function operator<<(basic_ostream &, const T *).
But it is a template accepting only pointers types, so when I pass
a MyString object it is not taken in consideration.

Isn't this an inconsistent behaviour?