Re: pointer to function as template parameter
"MaxMax" <none@none.com> wrote in message
news:%Uieg.15708$jP5.386172@twister1.libero.it...
I have a
template<class T, class TBase>
TBase* MyFunc(int *a, int *b)
{
T* pT = new T;
return static_cast<TBase*>(pT);
Why the cast? pT is already a TBase*. And isn't this design likely to result
in memory leaks? This is mysterious stuff.
}
If you write
int a = 7;
int b = 12;
TBase *p = MyFunc(&a, &b);
how is the compiler supposed to figure out the type of T or TBase? (The type
of the return result cannot be used.)
I think a template class may be what you need but it is hard to be sure from
what you have given us.
(the a and the b are used in some way in the true function)
(clearly TBase must be a base class of T to make it work)
I want to create something like
list<pointerfunctions> a;
If you have a list of objects, they must all be of the same type. However,
they can be pointers (better yet smart pointers) to a common base class.
Again, this suggests you really want a polymorphic class rather than a
function here.
How do I write the signature of the function? I can't use typedef because
there is a template...
--- Thanks