Re: Storing std::type_info

From:
=?ISO-8859-1?Q?Erik_Wikstr=F6m?= <Erik-wikstrom@telia.com>
Newsgroups:
comp.lang.c++
Date:
Sat, 11 Aug 2007 12:19:51 GMT
Message-ID:
<HPhvi.5955$ZA.2769@newsb.telia.net>
On 2007-08-11 16:02, Daniel Kraft wrote:

Hi all,

I tried to store a std::type_info value in my code so I didn't have to
call typeid more than once when checking if a polymorphic object is of
one of certain types, like this:

#include <typeinfo>

class A
{
  public:
   virtual int foo() { return 42; }
};

class B : public A
{};

class C : public A
{};

void foo(A& obj)
{
  std::type_info type(typeid(obj));

  if(type==typeid(B)) { ... }
  if(type==typeid(C)) { ... }
}

I found, however, that the copy-constructor of type_info was private; is
it save to store the value by reference:

const std::type_info& type(typeid(obj)); ?

This compiles fine, but I'm not sure whether this stores the reference
to a temporary object which is no longer valid when the comparison happens.

Is is ok to do this with references? Or is there any other way to store
the type_info or do I have to insert typeid(obj) everywhere in the ifs?


Yes, a const reference can be bound to a temporary.

Or you can use & to get the address of the type_info object (typeid
returns a reference) but in that case you should use type_info's ==
operator and not compare addresses of type_info objects, i.e.
void foo(A& obj)
{
   const std::type_info* type = &typeid(obj);

   if(*type==typeid(B)) { std::cout << "B\n"; }
   if(*type==typeid(C)) { std::cout << "C\n"; }
}

--
Erik Wikstr?m

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