Re: How to do "derived" type extensions?
Kira Yamato wrote:
On 2008-01-08 12:17:35 -0500, LR <lruss@superlink.net> said:
Kira Yamato wrote:
On 2008-01-08 09:18:53 -0500, LR <lruss@superlink.net> said:
Kira Yamato wrote:
Suppose class B is a subtype of class A, i.e.,
class B : public A
{
...
};
But now how do I do the following kind of morphism? Suppose I have
functions
void foo(const B &);
and
void bar(const A &);
I like to be able to declare a function pointer
void (*fp)(const B&);
and make "polymorphic" assignments like
p = foo; // this is ok in C++.
p = bar; // semantically this make sense, but C++ syntax
won't allow this!
Would it be acceptable to create a function,
void bar(const B &);
You mean
void foo(const B &);
No, that's not what I meant. I don't think that I made myself clear,
so I'll try again.
Untested, and not complete...
This is what I think you started with.
class A {
};
class B : public A {
};
void foo(const B &) {
}
void bar(const A &) {
}
now I suggest adding this function
void bar(const B &b) {
::bar( reinterpret_cast<const A&>(b) );
}
so you can
void (*fp)(const B&);
and
B b;
fp = bar; // will assign the address of void bar(const B &) to fp
fp(b);
fp = foo;
fp(b);
Yes. This is a nice work-around in the sense that it is direct and
seemingly not too much artifact.
Your solution is similar to the adaptor pattern (or am I misusing the
terminology here?).
I suppose in some ways, maybe not in others. However, consider this
well known, although I don't know the source, quote: "any [programming]
problem can be solved by introducing an extra level of indirection."
Thanks for the suggestion.
You're welcome.
Please don't overlook Pete Becker's correction and advice to use
static_cast instead of reinterpret_cast elsethread.
BTW, I've been thinking about this, and wondering about what you want to
do because I suspect this might be a little bit of a maintenance problem
if you're using this extensively in your code and your class structure
changes.
LR
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