Re: Permitting access to only a subset of the public methods

From:
muralive@gmail.com
Newsgroups:
comp.lang.c++
Date:
Thu, 17 Jul 2008 11:42:10 -0700 (PDT)
Message-ID:
<740cda0f-25f2-457a-a4a4-1c2805d912b0@k13g2000hse.googlegroups.com>
I am suspecting a fundamental misunderstanding of the underlying
problem and the simplified case presented here is quite reflecting
that. Anyway, passing a subclass of R to A/B isn't going to be able to
do anything to make certain public methods of R to unavailable to A
and B. I can think of a few solutions based on similar design
patterns, obscurity through encapsulation (containment) or
polymorphically though levels of base classes preferably abstract
(like interfaces in java).
So using your own example, contain R in RCA or RCAB and provide them
to A or B respectively or create a (fully abstract) AR and ABR,
inherit R from them, that is AR->ABR->R, construct R but pass R as AR
or ABR to A or AB respectively.
In both of the above cases, have public only those methods that A or B
should see.

- Murali.

On Jul 17, 11:19 am, Joe Greer <jgr...@doubletake.com> wrote:

fgh.vbn....@gmail.com wrote in news:e790868e-086d-4cb4-bb40-
2c0fbdde2...@w7g2000hsa.googlegroups.com:

Hi,

I'm not sure if i'm asking the question correctly but anyway here it
is.

Say I have 3 classes - class A, class B, class R.
1) A and B are the building blocks and R is like a repository that
stores objects of A and B.
2) A is at the lowest level and should "know about" only other As. B
should know only about As and other Bs.
3) R has 3 types of public methods - (i) methods to add A,B (ii)
methods to access A, B and (iii) all other methods.

For now I pass a pointer to R to both A and B so that they can access
information from R as required. However, this exposes all public
methods (ie., (i), (ii) and (iii)) of R to both A and B.

How do I change it so that A and B can only access methods of type
(ii)? (The rationale is that A/B will never add another A/B and they
shouldn't be doing anything else related to R). Is there a way to make
a subclass of R called Rsub and pass that pointer to A,B? Is that a
good way to do it?

I have included code below.

Thanks.

#include <iostream>
#include <vector>

using namespace std;

class A;
class B;
class R;

class A {
public:
    A (R* r, const int& i) : rp(r), N(i) {}
    int getN (void) const { return N; }
    void fA (const int& idx)
        {
            // Access an A object at index idx through rp
        }
private:
    R* rp;
    int N;
};

class B {
public:
    B (R* r, const string& s) : rp(r), str(s) {}
    string getStr (void) const { return str; }
    void fB1 (const int& idx)
        {
            // Access an A object at index idx through rp
        }
    void fB2 (const int& idx)
        {
            // Access a B object at index idx through rp
        }
private:
    R* rp;
    string str;
};

class R {
public:
    // Methods to add A, B
// void addA (const int& i) { A a(i); vA.push_back(a); }
// void addB (const string& s) { B b(s); vB.push_back(b); }
    void addA (const A& a) { vA.push_back(a); }
    void addB (const B& b) { vB.push_back(b); }

    // Methods to access information for A,B
    int getAN (const int& idx) const { return vA.at(idx).getN()=

; }

    string getBstr (const int& idx) const { return
vB.at(idx).getStr(); }
    // ... some more info

    // All other methods
    // ...
private:
    vector<A> vA;
    vector<B> vB;
};

int main() {
    R rep;

    A a1(&rep, 100);
    A a2(&rep, 200);
    rep.addA(a1);
    rep.addA(a2);
    cout << rep.getAN(0) << " and " << rep.getAN(1) << endl;

    // a2.fA(0); // should return info about a1

    B b1(&rep, "dog");
    B b2(&rep, "cat");
    rep.addB(b1);
    rep.addB(b2);
    cout << rep.getBstr(0) << " and " << rep.getBstr(1) << endl;

    // b2.fB1(0); // should return info about a1
    // b2.fB2(0); // should return info about b1

    return 0;
}


Well, the first thing that comes to mind is to use interfaces.

class IR_A {
public:
   virtual void addA(const A& a) = 0;
   virtual int getAN(const int& idx) = 0;
   virtual ~IR_A(){}

};

class IR_B {
public:
   virtual void addB(const B& b) = 0;
   virtual string getBstr(const int& idx) = 0;
   virtual ~IR_B(){}

};

class R : public IR_A, public IR_B {
public:
    // Methods to add A, B
// void addA (const int& i) { A a(i); vA.push_back(a); }
// void addB (const string& s) { B b(s); vB.push_back(b); }
     void addA (const A& a) { vA.push_back(a); }
     void addB (const B& b) { vB.push_back(b); }

     // Methods to access information for A,B
     int getAN (const int& idx) const { return vA.at(idx).getN(=

); }

     string getBstr (const int& idx) const { return
 vB.at(idx).getStr(); }
     // ... some more info

     // All other methods
     // ...
 private:
     vector<A> vA;
     vector<B> vB;
 };

Then, you change your A and B classes to use them...

 class A {
 public:
     A (IR_A * r, const int& i) : rp(r), N(i) {}
     int getN (void) const { return N; }
     void fA (const int& idx)
         {
             // Access an A object at index idx through rp
         }
 private:
     IR_A * rp;
     int N;
 };

 class B {
 public:
     B (IR_B* r, const string& s) : rp(r), str(s) {}
     string getStr (void) const { return str; }
     void fB1 (const int& idx)
         {
             // Access an A object at index idx through rp
         }
     void fB2 (const int& idx)
         {
             // Access a B object at index idx through rp
         }
 private:
     IR_B * rp;
     string str;
 };

Main can stay the same. If you want a bit more added security, you can
make all the methods of R which participate in IR_A or IR_B private. T=

hen

you can only access those methods through one of the two interfaces.

Hope that is of some help.

joe- Hide quoted text -

- Show quoted text -

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