Re: Polymorphism and inheritance

From:
newbarker@gmail.com
Newsgroups:
comp.lang.c++
Date:
Mon, 8 Sep 2008 03:55:21 -0700 (PDT)
Message-ID:
<90a27112-d6cc-4d47-9a2d-d9ea06533394@k7g2000hsd.googlegroups.com>
On 8 Sep, 11:22, Bart Friederichs <b...@tbwb.nl> wrote:

Hello,

I created the following inheritance:

class Parent {
public:
        void foo(int i);

};

class Child : public Parent {
public:
        void foo(int i, int i);

};

The following code fragment does not work (it doesn't compile, g++
complains about 'no matching function call for Child::foo(int)':

...
Child c;
int k = 0;
c.foo(k);
...

I assumed that by inheriting the base class, the 'Child' class would
have two 'foo' methods, with different parameters. Apparently not. Adding

void foo(int i) { Parent::foo(i); }

to the Child class, fixes it, but is that how it should be done? Why is
the Parent's foo() not polymorphised-inherited by Child?

TIA,
Bart


Bart,

Couple of things to get out of the way first:
1) There is no polymorphism at all. Polymorphism is when you have
virtual functions.
2) Child::foo() is illegal as it has two parameters called "i".

What you're attempting is overloading. When Child introduces a method
called foo, it hides all the other methods from its base classes with
the same name. You can still call it like this:

int main()
{
  Child c;
  int k = 0;
  c.Parent::foo(k); // <--- We want to call Parent's foo()
}

Another alternative is to unhide foo with Parent like this:

class Parent {
public:
    void foo(int i)
    {
    }
};

class Child : public Parent {
public:
    void foo(int i, int j)
    {
    }
    using Parent::foo; // <--- Unhide foo() from Parent
};

int main()
{
    Child c;
    int k = 0;
    c.foo(k);
}

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