Re: Getting non "const" pointers to object data using "const" members

From:
"Gingko" <Gingko@nospam.nospam>
Newsgroups:
microsoft.public.vc.language
Date:
Tue, 24 Mar 2009 10:17:12 +0100
Message-ID:
<uI26UFGrJHA.2552@TK2MSFTNGP04.phx.gbl>
"Ulrich Eckhardt" <eckhardt@satorlaser.com> a ??crit dans le message de
news:lmgm96-su7.ln1@satorlaser.homedns.org...

Gingko wrote:

The returned pointers are not arbitrary, they are *selected* parts of the
object, other parts are still expected to be not accessible.

My object is actually a tree container, and the member function explores
all branches for returning a flattened list of pointers to all leaves.


There are a few things you can do to achieve that, while not violating
type
safety or const correctness.

1. Separate the container part from the content:
 template<typename element_type>
 struct node
 {
   element_type value;
   node* parent;
   node* left;
   node* right;
 };
Make this a private nested class of the tree container.

2. Provide an interface to access the elements of the tree. One such
interface is an iterator (take a look at Boost's iterator builder
library).
Another such interface is a visitor:

 struct tree {
    ...
    template<typename Visitor>
       void visit(Visitor v);
    template<typename Visitor>
       void visit(Visitor v) const;
 };


My class system already more or less looks like that
But what is "Visitor v" ? A container for the flattened list ? Shouldn't it
be more likely something like "Visitor & v" ?

Note that this is not exactly the visitor pattern, since that is intended
to
do double dispatch rather. The function above will invoke "v(e)" for every
node's value 'e'. This allows you to e.g. create a flat list of all nodes,
but the list will point to const objects when you use the const overload
of
this function. Note that I would _not_ call it with every node but only
its
value, because the node is an internal thing to the tree.


How do you want the node to be modifiable (which is a primary requirement)
from the flattened list if the node is const or passed by value ?

Leaves are expected to be modifiable (and randomly accessible like in a
subscripted array), but I want the structure of the tree itself to be
protected.


You really support 'tree[index]'? That tempts to write horribly
inefficient
code like using a 'for(int i=0; ...)' loop to iterate the tree.


I am actually trying to implement it as a std::vector<Node *>, filled by
pointers without ownership.

I use a polymorphic member actually truely named "visit", which is a "const"
member implemented either for getting the pointer in the node itself or in
another class which is a sub-container for several nodes or nodes containers
(in that case, "visit" will recursively iterate for calling the "visit"
member of all of these nodes).

This polymorphic member has a "std::vector<Node *> & vNodeList" as argument.

The only problem is, as "visit" is a "const" member, which seems more or
less logical to me, it does not allow "vNodeList.push_back(this)" for
getting the pointer.
This will probably end by removing the "const"'ness of all "visit" members,
but I don't think that this will fully satisfy me.

Gilles

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