On 5 mai, 17:24, Noah Roberts <n...@nowhere.com> wrote:
GeeRay wrote:
Hi all,
I have this problem: I need to implement a class hierarchy where the
main class has a template method that will be inherited by the subclass.
Something like:
[cut]
On of this approach is to use dynamic polymorphism, that is if you can
define a same contract on your type. As an example if your foo is only
displaying a message with the data in parameter, your contract if that
the type should support (ostream<<T), you define the interface:
struct foo_ostreamable
{
virtual ostream& output(ostream&)const=0;
};
Then you define a templated foo_streambable implementation:
template<typename T>
struct foo_ostreamable_imp: foo_ostreamable
{
T value;
foo_ostreamable_imp(const T& t):value(t){}
virtual ostream& output(ostream& os)const{return os<<value;}
};
And finally the parameter of SuperClass::foo with templated
constructor:
struct foo_param
{
template<typename T>
foo_param(const T& t){data.reset(new foo_ostreamable_imp<T>(t));
scoped_ptr<foo_ostreamable> data;
};
// foo_param can be written into ostream
ostream& operator<<(ostream& os,const foo_param& p)
{
return p.data->output(os);
}
And finally, you define your classes:
class SuperClass
{
public:
virtual void foo(const foo_param&) const = 0;
};
class SubClass: public SuperClass
{
public:
virtual void foo(const foo_param& p) const { cout << p <<
endl;}
} ;
The compiler will automatically resolve with correct subtype:
SubClass s;
s.foo(1);
s.foo(0.1);
s.foo("bar");
...
If you want to keep/compare foo_param values, there is some management
to do such as deep copy and others to put it into canonical form. If a
type doesn't react as you want, you overload foo_param constructor.
There is an overhead but that depends on what you want.
--
Michael
Thank you very much, that's exactly what I was looking for.