Re: is it possible to create the functionality of a virtual template method?

From:
Michael Doubez <michael.doubez@free.fr>
Newsgroups:
comp.lang.c++
Date:
Wed, 23 Dec 2009 07:31:44 -0800 (PST)
Message-ID:
<8fd520fd-fba2-4196-9fa6-71ea07a72e1e@j4g2000yqe.googlegroups.com>
On 23 d=E9c, 13:43, "ted orange" <nos...@please.com> wrote:

"Michael Doubez" <michael.dou...@free.fr> wrote in message

news:7d56071c-3291-499d-b8c5-a36cc365e405@a21g2000yqc.googlegroups.com...
On 23 d=E9c, 11:04, "ted orange" <nos...@please.com> wrote:

"Michael Doubez" <michael.dou...@free.fr> wrote in message
news:7383d7f5-bc8f-446a-b6f3-ec139ff9f21b@r5g2000yqb.googlegroups.com..=

..

On 23 d=E9c, 09:54, "ted orange" <nos...@please.com> wrote:

I would like to have a container of objects where each object has a
template
method like so

template <class T>

void DoSomething(T& t);

so that I may, at runtime, pass various types to that method. The ty=

pe

will
be automatically dededuced.

I understand that virtual template methods are not permitted and tha=

t

containers may only store heterogeneous collections if they are
polymorphic.

Is there a mechanism by which I can attain my objective?


There are many ways with different trade-offs. It depends on the
contract you can make on T or on how much you can impact on the
objects.

Three examples:

[snip]

2 You can wrap T into a polymorphic object reflecting the contracts/
concepts on T and pass it to a virtual function. It comes at the cost
of reducing the range of type.

[snip]

Myself, I would favor the second solution because it provides high
control on the input types and keeps coupling low.

[snip]

I think I understand what you're saying but plz provide an example of 2=

 to

clarify. Thanks.


I have posted an example not so long ago:http://groups.google.fr/group/co=

mp.lang.c++/browse_frm/thread/724c2ca...

Here is a copy of the relevant example:
<quote>
One approach is to use dynamic polymorphism, that is if you can
define a same contract on your type. As an example if your foo is only
displaying a message with the data in parameter, your contract if that
the type should support (ostream<<T), you define the interface:

struct foo_ostreamable
{
  virtual ostream& output(ostream&)const=0;

};

Then you define a templated foo_streambable implementation:

template<typename T>
struct foo_ostreamable_imp: foo_ostreamable
{
  T value;
  foo_ostreamable_imp(const T& t):value(t){}

  virtual ostream& output(ostream& os)const{return os<<value;}

};

And finally the parameter of SuperClass::foo with templated
constructor:

struct foo_param
{
  template<typename T>
  foo_param(const T& t){data.reset(new foo_ostreamable_imp<T>(t));

  scoped_ptr<foo_ostreamable> data;

};

// foo_param can be written into ostream
ostream& operator<<(ostream& os,const foo_param& p)
{
 return p.data->output(os);

}

And finally, you define your classes:
class SuperClass
{
public:
        virtual void foo(const foo_param&) const = 0;

};

class SubClass: public SuperClass
{
public:
        virtual void foo(const foo_param& p) const { cout << p <<
endl;}

} ;

The compiler will automatically resolve with correct subtype:
SubClass s;
s.foo(1);
s.foo(0.1);
s.foo("bar");
...

If you want to keep/compare foo_param values, there is some management
to do such as deep copy and others to put it into canonical form. If a
type doesn't react as you want, you overload foo_param constructor.
</quote>


[snip]

I'm a bit confused (I struggle with abstract concepts). Why is your examp=

le

different from simply using polymorphism? Like this:

class Pet
{
public:
    virtual void Speak() = 0;

};

class Cat : public Pet
{
public:
    void Speak(){cout << "meow";}

};

class Dog : public Pet
{
public:
    void Speak(){cout << "woof";}

};

void DoSomething(const Pet& p)
{
    p.Speak();

}

Is it that in your example the contract for what a type is permitted to d=

o

is specified outside its definition?


In your example, Cat and Dog have a common ancestor Pet. Which is not
always the case. In your original post, you would like to pass in a
virtual function types that are not related.

If you used simple polymorphism, you would have to explicitely
instanciate a wrapper for each type you want to support

Wrapper param1(1);
s.foo(param1);
Wrapper param2(0.1)
s.foo(param2);
Wrapper param3("bar")
s.foo(param3);

or you would have to restrict to const object

s.foo(1); // s.foo(Wrapper(1))
s.foo(0.1); // s.foo(Wrapper(0.1));
s.foo("bar"); // s.foo(Wrapper("bar"));

Depending on your design you may need one solution or the other.

--
Michael

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