Re: One more foolishness of the C++ Standard

My example was

A{};
B: public A {};

A a;
B b = a;

If there is a constructor in the B class

explicit B( const A & )

then
B b = a;

will not be allowed.

Consider a class

template <typename T>
class Point : public std::pair<T, T>
{
    T &x;
    T &y;
    template <typename U, typename V>
    Point( const std::pair<U, V> & );
    ...
};

and try to write for it three operators

Point + Point;
Point + std::pair;
std::pair + Point

such a way that

std::pair + std::pair

will be impossible.

Vladimir Grigoriev

"Duane Hebert" <spoo@flarn.com> wrote in message
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