Re: Does object have function?

From:
Goran Pusic <goranp@cse-semaphore.com>
Newsgroups:
comp.lang.c++
Date:
Fri, 29 Oct 2010 00:48:48 -0700 (PDT)
Message-ID:
<bf9d4248-d885-485b-8909-e7ff2e2ab52c@l20g2000yqm.googlegroups.com>
On Oct 29, 12:01 am, "Jim Langston" <tazmas...@rocketmail.com> wrote:

What I am trying to accomplish: I have a map of polymorphic objects and
these objects may have certain methods defined or not. If the instance=

 has

the method then I want to call it, otherwise not.


Are these methods all of same signature (e.g. one "int" param)? If so,
then you can do this:

struct base;

typedef int (*pFunc)(base&, int);

struct base
{
  virtual pFunc GetFunc(int whichOne) const = 0;
};

struct derived : public base
{
  virtual pFunc GetFunc(int whichOne) const
  {
    return (7 == whichOne) ? &derived::func : NULL;
  }
  static int func(base&, int) {/*...*/ return 0; }
};

//and then

void f(base& b)
{
  pFunc f = b.GetFunc(7);
  if (f)
    f(b, 1);
}

(That's +/- the same as Paavo's suggestion with message maps, but you
choose your function signature, and, GetFunc allows you to choose//
refuse giving out pFunc at run-time.)

If your functions are of varying signatures, then I would go for mix-
in inheritance and dynamic_cast is better (Fooer example here). In
fact, I see nothing wrong with Fooer example at all. Inspecting if an
object has a particular interface isn't all that bad, after all.
( Inspecting for a lot of of them, which you seem to be doing,
however, smells a bit bad ;-) ).

Goran.

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