Re: Does object have function?

From:
Bogdan <cristeab@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Sat, 30 Oct 2010 09:55:15 -0700 (PDT)
Message-ID:
<2f34f464-3ceb-4255-87a9-d574ee41c85c@l17g2000yqe.googlegroups.com>
On Oct 29, 1:01 am, "Jim Langston" <tazmas...@rocketmail.com> wrote:

What I am trying to accomplish: I have a map of polymorphic objects and
these objects may have certain methods defined or not. If the instance=

 has

the method then I want to call it, otherwise not.

It is trivial to create a virtual function for a few functions. But I =

would

have to add every single function that could be interfaced.

I would just to somehow be able to tell if an instance has a function
available. Consider:

#include <iostream>

class Base {
public:
   virtual ~Base() {}

};

class DerivedOne : public Base {
public:
   void foo() { }

};

class DerivedTwo : public Base {
public:
   void foo() { }

};

class DerivedThree: public Base {

};

int main() {
   Base* bps[3];
   bps[0] = new DerivedOne();
   bps[1] = new DerivedTwo();
   bps[2] = new DerivedThree();

   for ( auto i = 0; i < 3; ++i ) {
      DerivedOne* thisOne = dynamic_cast<DerivedOne*>( bps[i] );
      if ( thisOne )
         thisOne->foo();
   }

}

I would have to dynamic_cast for every class that had a foo() defined to
execute all foos. Is there a way to do what I want?

Jim Langston


If you need to add some functionality to objects, not classes, why not
use the decorator design pattern? This would imply that the method you
does either nothing or does a specific thing.

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