Re: Generic ostream operator<<?

From:
88888 Dihedral <dihedral88888@googlemail.com>
Newsgroups:
comp.lang.c++
Date:
Tue, 26 Jun 2012 17:46:06 -0700 (PDT)
Message-ID:
<689d2d24-49b2-425c-9b48-0b58fd9b2b7b@googlegroups.com>
Gerhard Fiedler=E6=96=BC 2012=E5=B9=B46=E6=9C=8820=E6=97=A5=E6=98=9F=E6=9C=
=9F=E4=B8=89UTC+8=E4=B8=8A=E5=8D=883=E6=99=8242=E5=88=8652=E7=A7'=E5=AF=
=AB=E9=81=93=EF=BC=9A

Victor Bazarov wrote:
 

On 6/19/2012 3:30 PM, Gerhard Fiedler wrote:

I want to be able to stream custom classes to ostreams like this:

MyClass foo;
myStream<< foo;

AIUI, this requires an operator<<() with this signature:

std::ostream&operator<<( std::ostream&str, MyClass const&printable );

In order to avoid creating such a function for every class, I tried a
template like this:

template< class Printable>
std::ostream&operator<<( std::ostream&stream,
    Printable const&printable )
{
    printable.print( stream );
    return stream;
}

(All the classes in question have a public member function "void print=

(

std::ostream&stream )".)

However, with this I get tons of errors like "'operator<<' is
ambiguous".

Is there a way to define this template function so that it is only
instantiated for classes that implement this print() function? (I coul=

d

make the name such that it is very unlikely that any other class has
such a name.)

Or is there another way to avoid having to define such a global
operator<< for every class with ostream support?

 
Have you considered using polymorphism at all, or is it out of fashion=

 

already?

 
Thank you for your response. In fact I didn't consider it at first,
reconsidered it after reading your post, and threw it out again :)
 
This is meant to work for an indeterminate number of classes of a bigger
system, some of which are not polymorphic at all for various reasons. I
don't want to put this constraint on all the classes that potentially
may want to use this interface.
 
If there was a way without polymorphism, I would prefer this.
 
Gerhard


Gerhard Fiedler=E6=96=BC 2012=E5=B9=B46=E6=9C=8820=E6=97=A5=E6=98=9F=E6=9C=
=9F=E4=B8=89UTC+8=E4=B8=8A=E5=8D=883=E6=99=8242=E5=88=8652=E7=A7'=E5=AF=
=AB=E9=81=93=EF=BC=9A

Victor Bazarov wrote:
 

On 6/19/2012 3:30 PM, Gerhard Fiedler wrote:

I want to be able to stream custom classes to ostreams like this:

MyClass foo;
myStream<< foo;

AIUI, this requires an operator<<() with this signature:

std::ostream&operator<<( std::ostream&str, MyClass const&printable );

In order to avoid creating such a function for every class, I tried a
template like this:

template< class Printable>
std::ostream&operator<<( std::ostream&stream,
    Printable const&printable )
{
    printable.print( stream );
    return stream;
}

(All the classes in question have a public member function "void print=

(

std::ostream&stream )".)

However, with this I get tons of errors like "'operator<<' is
ambiguous".

Is there a way to define this template function so that it is only
instantiated for classes that implement this print() function? (I coul=

d

make the name such that it is very unlikely that any other class has
such a name.)

Or is there another way to avoid having to define such a global
operator<< for every class with ostream support?

 
Have you considered using polymorphism at all, or is it out of fashion=

 

already?

 
Thank you for your response. In fact I didn't consider it at first,
reconsidered it after reading your post, and threw it out again :)
 
This is meant to work for an indeterminate number of classes of a bigger
system, some of which are not polymorphic at all for various reasons. I
don't want to put this constraint on all the classes that potentially
may want to use this interface.
 
If there was a way without polymorphism, I would prefer this.
 
Gerhard


Lets face polymorphism seriously for a compiled program in the runtime.

V-tables of functors are necessary for objeccts with actions
in derived classes to use methods in their base classes propperly.

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