Re: What's polymorphic in CRTP

From:
Cholo Lennon <chololennon@hotmail.com>
Newsgroups:
comp.lang.c++
Date:
Fri, 15 Feb 2013 13:55:12 -0300
Message-ID:
<kflp6c$i9b$1@speranza.aioe.org>
On 02/15/2013 01:33 PM, ?? Tiib wrote:

On Friday, 15 February 2013 18:18:47 UTC+2, Cholo Lennon wrote:

How about this?


It is example that works but does not achieve much else but inefficiency.
;-)


Why the example is inefficient? The call to Derived::onStatic is
resolved at compile time.

Also, in order to simplify the code I put the dynamic/static variants in
the same class.

The example shows static polymorphism as is used in ATL (WTL). It was
not intended to be used/interpreted in another way.

#include <iostream>

template<class T>
class Base {


Note that T is meant to be derived class.
So you can not use Base<Derived>* as dynamically polymorphic interface
pointer for several different "Derived"s.

public:
    void callDynamic()
    {
      onDynamic();
    }

    void callStatic()
    {
      T* pThis = static_cast<T*>(this);
      pThis->onStatic();
    }

    virtual void onDynamic()
    {
      std::cout << "Base::onDynamic" << std::endl;
    }

    void onStatic()
    {
      std::cout << "Base::onStatic" << std::endl;
    }

};

class Derived: public Base<Derived> {

public:

    virtual void onDynamic()
    {
      std::cout << "Derived::onDynamic" << std::endl;
    }

    // "pseudo virtual" function :-)
    void onStatic()
    {
      std::cout << "Derived::onStatic" << std::endl;
    }
};

int main(int, char**)
{
    Derived derived;
    derived.callDynamic();
    derived.callStatic();
}

Also, try commenting out functions in Derived class to see what happens


Just try making it with Derived1, Derived2 and Derived3 and you see where you
went wrong. Do not mix CRTP with dynamic polymorphism. Use typical
pure abstract interface base and multiple inheritance side by side with
CRTP if you need to mix them.


--
Cholo Lennon
Bs.As.
ARG

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