Re: How to pass a binary_function functor as an argument?

From:
Carl Barron <cbarron413@adelphia.net>
Newsgroups:
comp.lang.c++.moderated
Date:
Tue, 27 Mar 2007 21:28:31 CST
Message-ID:
<270320072014427754%cbarron413@adelphia.net>
In article <1175020906.822418.69400@l77g2000hsb.googlegroups.com>,
<t_littell@yahoo.com> wrote:

I want to pass a binary_function<double, double, double> functor
object as an argument into another function. So, I tried the
following which does not work with std::accumulate():


    std::binary_function<...> does not make a class polymorphic in the
sense that it knows what the derived class is. std::binary_function<...>
is a convience struct containing three typedefs nothing else.

  The simplest solution is to make the functor a template parameter
and pass it by value or const reference.

    template <class Functor>
    double foo(std:::vector<double> &v,double init,Functor f)
    {
       return std::accumulate(v.begin(),v.end(),init,f):
    }

    if you don't want a template use boost::function<...> or
tr1::function<...> to hold the functor, then foo is not a template
function
    double foo(std::vector<double>const &v,double init,
       boost::function<double(double,double)> f);

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