Re: getting a name of a polymorphic type
irek.szczesniak@gmail.com (Irek Szczesniak) wrote (abridged):
I know that typeid(*this).name() is not portable. Therefore I
resorted to implementing my own virtual function that returns the
name of the class. Nonetheless, is there any portable way so that I
don't need to keep implementing this function for new classes?
There is no better version of name() than the one you found.
You don't have to use virtual functions. You can instead use type_info as
the key into a map, and so register types that don't have any virtual
functions. It's better to use the entire type_info as the key, rather
than just the name.
There isn't a way to make the registration automatic, or even to enforce
it at compile-time. However, you can check that it has been done
correctly. You can also use macros to make registration easier.
-- Dave Harris, Nottingham, UK.
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