Re: Isn't this a polymorphic call?
* James Kanze:
On May 29, 2:15 am, "A. Bolmarcich" <agge...@earl-grey.cloud9.net>
wrote:
On 2008-05-28, Arindam <arindam.muker...@gmail.com> wrote:
On May 29, 2:14 am, Victor Bazarov <v.Abaza...@comAcast.net> wrote:
Arindam wrote:
#include <cstdio>
struct Test {
void bar() {
foo();
}
private:
virtual void foo() {
printf("Test\n");
}
};
struct Test2 : public Test {
void foo() {
printf("Test2\n");
}
};
int main(int argc, char* argv[])
{
Test2 v;
v.bar();
}
Does the call to v.bar() amount to a polymorphic
invocation of foo()?
Have you tried it? If you have, what happened? If not, why not?
Yes - it prints Test2. So this should be polymorphic right?
It is not polymorphic according to the inventor of C++, who
wrote in "The C++ Programming Language (Third Edition)":
"To get polymorphic behavior in C++, the member functions called must
be virtual and objects must be manipulated through pointers or
references. When manipulating an object directly (rather than through
a pointer or reference), its exact type is known by the compiler so
that run-time polymorphism is not needed."
And? He's calling foo() through a pointer (this), and the call
is resolved polymorphicly.
I think the question is (nearly) meaningless. The standard doesn't guarantee
how any call is resolved at the machine code level. E.g. in this case the
compiler may inline everything so that there's no call instruction.
Cheers,
- Alf
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