Re: "comparable" interface for generic/templated objects?
* ld:
On 8 f?v, 12:11, "Alf P. Steinbach" <al...@start.no> wrote:
* ld:
On 8 f?v, 03:55, vk <vmi...@gmail.com> wrote:
thanks!, that does help.
No it doesn't since you said that your type is unknown at compile
time. Overloading will not catch the right type and hence operator.
That's just meaningless, sorry.
If you try to create an example you will perhaps see why it's meaningless.
If you don't see it then just post your example in this group and you'll have it
examined and commented on by competent folks.
I thought that after two decades of using C++, I started to know a bit
of it.
To avoid wasting the time of everybody, you competent folk could show
us a nice example where overloading solve the problem of comparing two
polymorphic types, as mentioned by the OP.
C++ is not Java, and I think that was what the OP asked about, how to do things
in C++. Not how to translate the Java mechanically to equivalent C++. E.g., C++
has user defined operators and doesn't have a common Object base class.
std::priority_queue is an example of how to do things in C++.
Could you perhaps quote where the OP or anyone else (except yourself) mentioned,
for C++, "overloading", "polymorphic" and "comparing two ... types". Or could
you perhaps quote where such was mentioned for Java. I'm sorry but I can't
recall reading that earlier.
TIA.,
- Alf