Re: Confusion between this and *this on website -- possible error

From:
red floyd <no.spam.here@example.com>
Newsgroups:
comp.lang.c++
Date:
Sun, 29 Mar 2009 18:56:30 -0700
Message-ID:
<pFVzl.22346$c45.15599@nlpi065.nbdc.sbc.com>
Alf P. Steinbach wrote:

* pauldepstein@att.net:

Below is pasted from a website:

QUOTE BEGINS HERE

HOWTO: Covariant Return Types in C++
20060406T0140

Covariant return types are a useful feature of the C++ language that
could save you from doing some extra, unnecessary work in a few com
mon situations. They can also make the intended purpose of your
functions more clear. This HOWTO explains what they are, how to use
them, a nd gives some common sample applications.

Consider a simple inheritance hierarchy such as that shown here:

  Base
   |
   v
Derived

Often, the derived class has a polymorphic function which returns a
more specific (i.e. more derived) type than the base class. This is
per fectly legal, since the pointer is automatically downcast to the
base class type.

A common use of this (but by no means the only one) is a clone()
method:

class Base {
public:
    virtual Base* clone() const
    {
        return new Base(this);
    }
};

class Derived : public Base {
public:
    virtual Base* clone() const
    {
        return new Derived(this);
    }
};

QUOTE ENDS HERE

I would expect to see new Derived(*this) and
new Base(*this)


Right.

Is the website in error or am I in error?


The website.


On top of that, they're not even showing covariant return types.
They're showing simple virtual overriding.

It should be:

class Derived : public Base {
   public:
     virtual Derived* clone() const
     {
       return new Derived(*this);
     }
};

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