Re: Variables in for loop (style issue)
Walter Bright <walter@digitalmars-nospamm.com> writes:
Walter Bright wrote:
int x = 10;
const int& end = x;
for (int i = 0; i < end; i++)
{
x = 7;
printf("i = %d\n", i);
}
Note that this is legal, standards conforming code. It doesn't use
pointers, casts, unions, mutables, and it's single threaded. There's no
attempt to subvert the type system. It's even const-correct.
But 'end', despite being 'const', has its value change during the loop.
It isn't loop invariant.
....
So what has const as type modifier, as well as const-correctness,
brought to the table to justify all the effort and hype spent on it?
There's got to be a better way.
Funny that you decided to pick on const here. You could just as
easily indict references.
--
Dave Abrahams
Boost Consulting
www.boost-consulting.com
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