Re: conversion from array to reference to pointer

#include <iostream>

int main(void)
{
    char array[] = {'a', 'b', 'c'};
    char *ptr = "def";

    char* const &p = reinterpret_cast<char* const &>(array);
    char* const &q = reinterpret_cast<char* const &>(ptr);

    char *& p1 = reinterpret_cast<char*&>(array);
    char *& q1 = reinterpret_cast<char*&>(ptr);

    // If p is a reference to a pointer, then it should be used
    // just as a normal pointer.
    printf("%c %c %c\n", p, p+1, p+2);

    // If p is a reference to a pointer, then it should be used
    // just as a normal pointer.
    printf("%c %c %c\n", q[0], q[1], q[2]);

    // If p is a reference to a pointer, then it should be used
    // just as a normal pointer.
    printf("%c %c %c\n", p1, p1+1, p1+2);

    // If p is a reference to a pointer, then it should be used
    // just as a normal pointer.
    printf("%c %c %c\n", q1[0], q1[1], q1[2]);

    // If p really is a reference, then this line shouldn't compile.
    // p = 0;
    // If q really is a reference, then this line shouldn't compile.
    // q = 0;

    // If p1 really is a reference, then this line shouldn't compile.
    p1 = 0;
    // If q1 really is a reference, then this line shouldn't compile.
    q1 = 0;

    // The previous lines compile, hence they aren't references!

    return (int)p;
}

uvts_cvs@yahoo.com wrote:


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