Re: Reference is not a member of class?
Oleg wrote:
This code compiles on Test Drive Comeau C++ Online and on VC 7.1. So, I
assume that it is standard compliant. but why it is allowed to modify
non-const reference in const method?
It isn't.
class test
{
public :
test(int& i) :
m_i(i) {}
void f() const
{
m_i = 0;
This modifies the int referred to by the reference.
It's not a reference-to-const, so that's legal, just
as it would be legal to write *m_pi = 0; if you had
a member m_pi of type int* instead of your reference
member. Constness isn't transitive; the fact that
the test object is const means that its members are
const, but things they point/refer to don't become
const because of that. It's the difference between
a pointer that can't be changed, and a pointer-to-const.
}
private :
int& m_i;
};
int main()
{
int i = 1;
const test t(i);
t.f(); // set i to 0
}
Hope this helps,
James
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