Re: dynamic function definition
cesco wrote:
I need to define the body of a function in the constructor of a class.
Impossible. You cannot define a function, member or free, in the body of
another function.
For example, the class has a member function Log (that is the public
interface of the class), but I want the body of this function to be
defined as something or as something else in the constructor of the
class:
You have not revealed any details of the condition upon which the
behaviour depends. Is it decided at runtime or at compile time which
version is to be called? In the former case, does the condition change
during the lifetime of a particular MyClass object? Assuming a runtime
decision, that the condition is part of the state of MyClass, and that
MyClass::Log() works like a toggle switch, it seems that a boolean
member and a simple conditional expression would do the trick:
class MyClass
{
public:
MyClass();
void Log(const int& id, const int& value);
private:
void LogON(const int& id, const int& value);
void LogOFF();
bool myLogIsOn;
};
MyClass::MyClass
() // don't forget the parentheses
: myLogIsOn (/* put a ?: expression here if the condition is
simple enough, otherwise initalize myLogIsOn
in the body of the constructor */)
{
}
void MyClass::LogON(const int& id, const int& value)
{
// do something like push_back
}
void MyClass::LogOFF()
{
// do nothing
}
void MyClass::Log(const int& id, const int& value)
{
if (myLogIsOn)
{
this->LogOFF();
myLogIsOn = false;
}
else
{
this->LogON(id, value);
myLogIsOn = true;
}
}
By the way, is there a particular reason why you pass id and value as
const references instead of by value?
Please be more specific if this should not solve your problem.
--
Gerhard Menzl
#dogma int main ()
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