Re: problem with accessing a "struct" using "->"
On Mar 29, 3:31 pm, "Gavin Deane" <deane_ga...@hotmail.com> wrote:
void print_addr(const address p) // print_addr doesn't need to change
the contents of p
good idea :-)
{
using std::cout;
using std::endl;
cout << p.name
<< '\n'
<< p.country
<< endl;
}
Maybe it's what you meant, but if you go this way I see no reason why
print_addr shouldn't take a const reference
void print_addr(const address& p) { ... }
it takes a /const reference/ , no problem.
my programme works now, fine,no troubles. THANKS:
------------ PROGRAMME -------------
/* Stroustrup, 5.6 Structures
STATEMENT:
this programmes has 3 parts:
1.) it creates a "struct", named "jd", of type "address".
2. it then adds values to "jd"
3.) in the end it prints values of "jd".
*/
#include<iostream>
#include<vector>
struct address;
void fill_addr(address&); // assigns values to a struct of type
"address"
void print_addr(const address&); // prints an address struct
struct address {
char* name;
char* country;
};
int main()
{
address jd; // an "address" struct
address& ref_jd = jd;
fill_addr(ref_jd);
print_addr(ref_jd);
return 0;
}
void fill_addr(address& jd)
{
jd.name = "Niklaus Wirth";
jd.country = "Switzerland";
}
void print_addr(const address& p)
{
using std::cout;
using std::endl;
cout << p.name
<< '\n'
<< p.country
<< endl;
}
-------- OUTPUT -------------
[arch@voodo tc++pl]$ g++ -ansi -pedantic -Wall -Wextra
5.6_structures.cpp
[arch@voodo tc++pl]$ ./a.out
Niklaus Wirth
Switzerland
[arch@voodo tc++pl]$