Re: reference vs pointer
Erik Wikstr?m wrote:
On 2007-05-01 19:19, Rolf Magnus wrote:
Erik Wikstr?m wrote:
On 2007-05-01 18:21, sam_cit@yahoo.co.in wrote:
Hi Everyone,
A reference is a alias for a variable.
int i =5;
int &b = i;
Is memory allocated for the reference variable like a pointer
variable?
No, try this:
int* ip = &i;
int* bp = &b;
if (ip == bp)
std::cout << "Same\n";
What does this have to do with the question if a reference takes up
memory?
Well, basically if it takes up memory then it has an address, and
using the address-of operator returns the address of it's operand,
Does it, now?
#include <iostream>
class TakesUpMemory_OrDoesIt
{
public:
TakesUpMemory_OrDoesIt* operator&() const { return 0; }
};
int main()
{
TakesUpMemory_OrDoesIt d, &rd = d;
std::cout << &d << ',' << &rd << std::endl;
}
so
if a reference did take up memory then the address-of operator would
return its address.
Aha...
V
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