Re: very simple pass by reference question

From:
Lionel B <me@privacy.net>
Newsgroups:
comp.lang.c++
Date:
Wed, 2 May 2007 08:31:26 +0000 (UTC)
Message-ID:
<f19i8u$gom$4@south.jnrs.ja.net>
On Wed, 02 May 2007 12:33:26 +0800, michael wrote:

Hi All,

How do I pass a reference to a pointer and update the pointer in the
function? I have:


#include <iostream>
#include <string>

using namespace std;

void goGetString(char *str){


void goGetString(char*& str){ // takes _reference_ to pointer

    string inString;

    cin >> inString;
    str = new char[inString.length()+1];
    strcpy(str, inString.c_str());
    cout << "String is " << str << endl;
}

int main(){
    char *someStr;

    goGetString(&*someStr); // ??? This is just someStr


      goGetString(someStr);

    cout << "String was " << someStr << endl;


      delete [] someStr; // prevent memory leak

}

why is someStr not changed ?


It wasn't changed because you passed the pointer in to goGetString() by
_value_.

BTW, why not let goGetString take a string& as parameter, rather than
using char* ?

#include <iostream>
#include <string>

using namespace std;

void goGetString(string& str)
{
    cin >> str;
    cout << "String is " << str << endl;
}

int main()
{
    string someStr;

    goGetString(someStr);
    cout << "String was " << someStr << endl;
}

Much simpler and less error-prone.

--
Lionel B

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