Re: Nonstatic member example?

From:
Salt_Peter <pj_hern@yahoo.com>
Newsgroups:
comp.lang.c++
Date:
Mon, 31 Dec 2007 01:27:42 -0800 (PST)
Message-ID:
<5862495b-ac63-48ae-9105-447cf0edd7da@r60g2000hsc.googlegroups.com>
On Dec 30, 11:24 pm, fl <rxjw...@gmail.com> wrote:

Hi,
There is a question about nonstatic member. C++ primer says: A
nonstatic member is restricted to being declared as a pointer or
reference to an object of its class. It only gives an example of
pointer *b.

class Bar {
public:

private:
static Bar a; // OK
Bar *b; // OK
Bar c; // error

My question is how a nonstatic member is declared as a reference to an
object of its class. Because a reference is legal only after the
original variable has been declared, where is the original object? I
feel it is really bizarre. Could you give me an example? Thanks in
advance.

private variable


the original object, in a special case like this one, would have to
refer to itself, which would then basicly mean that such a class could
not have a static member since the static member has no 'this'.
Its a special case, don't dissmiss references. They solve many, many
problems.

[10.7] Should you use the this pointer in the constructor?
http://www.parashift.com/c++-faq-lite/ctors.html#faq-10.7

#include <iostream>

class A
{
  const A& r_a;
public:
  A() : r_a(*this) { }
  A(const A& copy) : r_a(copy) { }
  A& operator=(const A& rhv); // disabled
  A const& get_r() const { return r_a; }
};

void foo(const A& r)
{
  std::cout << "&r = " << &r;
  std::cout << "\tr.r_a = " << &r.get_r();
  std::cout << std::endl;
}

int main()
{
  A a;
  foo(a);
  A another = a; // is NOT an assignment
  foo(another);
}

/*
&r = 0x7fff0f2e1930 r.r_a = 0x7fff0f2e1930
&r = 0x7fff0f2e1920 r.r_a = 0x7fff0f2e1930
*/

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