Re: Copy constructor doesn't get called when initialized by function returning object of same class
On 2008-06-12 12:14:43 +0200, dizzy <dizzy@roedu.net> said:
abhash wrote:
I am bit puzzled at the following piece of code I tried:
------------------------------------------------------------
#include <iostream>
using namespace std;
class Test {
public:
Test() { cout<<"Cons\n";}
Test(Test& a) { cout<<"Copy cons\n";}
You probably mean Test(Test const&).
};
Test fun()
{
return Test();
}
int main()
{
cout<<"First way of initialization\n";
Test t1;
Test t2 = t1;
cout<<"\nSecond way of initialization\n";
Test t3 = fun();
return 0;
}
OUTPUT (when compiled on CC compiler) :
First way of initialization
Cons
Copy cons
Second way of initialization
Cons
First of all if you really had your ctor taking a reference to non const as
you showed above then you are using a broken compiler. Your compiler should
have complained of not finding a Test(Test const&) ctor version.
How do you know that it didn't?
--
Pete
Roundhouse Consulting, Ltd. (www.versatilecoding.com) Author of "The
Standard C++ Library Extensions: a Tutorial and Reference
(www.petebecker.com/tr1book)
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