foolsmart2...@gmail.com writes:
for += operation, my code is:
ComplexNum ComplexNum::operator += (const ComplexNum& rhs) const
{
ComplexNum ans;
ans.real += rhs.real;
ans.imaginary += rhs.imaginary;
return ans;
}
here is lecturer's comment:
+= should be different. a += b means a = a + b
Your lecturer should've also told you that your results are undefined since
the contents of the ans object are, apparently, not initialized. Your +=
operation on ans's members are applied to, apparently, uninitialized members
of this object. This would be the same as writing:
int x;
x += 4;
Obviously, the results of this are undefined.
therefore *this object (i.e. a) should be updated with the answer.
Correct.
Do anyone know how to write += operation?
Yes, but why don't you try to figure this out yourself. Look around, there
are plenty of examples of assignment operators for other classes. Here are
two free clues:
1) operator += modifies this object, therefore it cannot be a const
function (well, it can be, but you're not there, yet).
2) The assignment operator, be it operator =(), operator +=(), operator
-=(), or anything else, traditional does not return another instance of the
object, but rather a reference to this, modified, object.
application_pgp-signature_part
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I make it a friend function.