Re: Is this String class properly implemented?

From:
SG <s.gesemann@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Sat, 18 Apr 2009 08:46:59 -0700 (PDT)
Message-ID:
<ec6d71e0-c611-40a8-88cd-de843e12bd1e@w40g2000yqd.googlegroups.com>
On 18 Apr., 17:22, kevintse.on...@gmail.com wrote:

Oh, I have clicked the wrong link, and only replied to the author SG


Let me include it here.

On Sat, Apr 18, 2009 at 5:18 PM, kevintse.on...@gmail.com wrote:

On Apr 18, 8:44 pm, SG <s.gesem...@gmail.com> wrote:

kevintse.on...@gmail.com wrote:

[...]

[...]

Actually, I intended to write an *unmutable* String, which only had
logical length, its length was not supposed to be changeable. This is
also the Java implementation of the String class. huh, I took the idea
from Java.


OK.

        operator const wchar_t* () const {
                return value;
        }


This is dangerous since this allows *implicit* conversion to a pointer
that points to memory that is *managed* by the string object. If the
string object dies and deletes the char array you basically have an
invalid pointer.


So if I want to return a C style string, I have to allocate new memory
for the string? and let the caller of the function deal with the
deallocation of the memory? But, most of the time, that I call this
function is just to obtain a C style string that can be output with
"iostream" related functions.


I haven't said anything against returning your internal wchar_t*
converted to pointer-to-const. I reasoned against an implicit
conversion operator.

        ~String(){
                size = 0;
                delete [] value;
        }


"size = 0;" is pretty much useless here.


Set size to zero is necessary, because I return "size" directly when
the "length()" function is called, this function tells the actual size
of the String. And this is definitely more efficient than calling
"wcslen(value)" everytime we need a "size".


You're not entirely familiar with the concept of destructors, are you?

        String trim();
        String trimLeft();
        String trimRight();


...are just three examples that could have been free functions
instead. Also, since you seem to be creating a new String object for
the result as return value you seem to have forgotten 'const'
qualifiers.


I was refering to the Java implementation of the class in which these
functions return new Strings, so, you know, I copied... oh, Java does
not have a pointer, or a reference...


I know that. But that's beside the point.

OK, these functions are all supposed to return references for better
efficiency, cause I am using C++.


....and what kind of reference would that be? A reference to the
object itself? Do you want these functions to mutate the String
object or just return a modified copy?

Never ever return a reference to a non-static function-local object.
Never ever.

        String operator=(String& str);


Your copy assignment doesn't take a reference-to-const String?


Oh, I have forgotten that...


Cheers!
SG

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