Re: Explicit specialization [ Template ]

Hi there,

I'm trying to Override a generic version of swapvalue for char. But
it still call's the generic version. Here is the sample code -

template<typename T>
void swapvalues(T& src, T& dest)
{
T temp;
temp = src;
src = dest;
dest = temp;
cout<<"Inside swapvalue [template]"<<endl;
}

// Override of generic version.
void swapvalues(char& src, char& dest)
{
         /*
char* temp = NULL;
*temp = src;
src = dest;
dest = *temp;
         */
cout<<"Inside swapvalue [char]"<<endl;
cout<<"src = "<<src<<" : dest = "<<dest<<endl;

}

int main()
{
int i=5, j = 7;
char* srcCh = "ABC";
char* destCh = "XYZ";

swapvalues(srcCh, destCh); // Template version is called, despite
address being passed.

        // Isn't this the correct way of passing char* to char& ?
//swapvalues(*srcCh, *destCh); // Rt way of calling