Re: Why extracting string from stringstream(a) fails?

From:
"Johannes Schaub (litb)" <schaub-johannes@web.de>
Newsgroups:
comp.lang.c++
Date:
Sun, 25 Oct 2009 19:13:07 +0100
Message-ID:
<hc24fk$9b2$00$1@news.t-online.com>
Maxim Yegorushkin wrote:

On 25/10/09 06:17, Mc Lauren Series wrote:

On Oct 25, 3:28 am, Victor Bazarov<v.Abaza...@comAcast.net> wrote:

Mc Lauren Series wrote:

#include<iostream>
#include<sstream>

using namespace std;

int main()
{
     string a("test");
     string b;
     stringstream(a)>> b;
}

When I try to execute this code, I get errors:

foo.c: In function 'int main()':
foo.c:10: error: no match for 'operator>>' in
'std::basic_stringstream<char, std::char_traits<char>,
std::allocator<char> >(((const std::basic_string<char,
std::char_traits<char>, std::allocator<char> >&)((const
std::basic_string<char, std::char_traits<char>, std::allocator<char>

*)(& a))), std::operator|(_S_out, _S_in))>> b'


Why does this error occur? Isn't stringstream(a) supposed to behave
just like a stream? With cout I can extract string into a string
variable. Then why not here?


The operator>> is a non-member. It takes the first argument by a
non-const reference, which cannot be initialized with a temporary.
Define a named variable and you will be able to do what you want:

      stringstream sa(a);
      sa>> b;

There is a trick to overcome this particular limitation, but it's not
the best approach. You can do something like that

      stringstream(a)>> boolalpha>> b;

which invokes a non-const member function (which is OK for temporaries)
and the function (that "outputs" a manipulator) returns a non-const
reference, which then can be passed to the non-member operator<<.


If>> is a non-member, why does this work?


Some stream operators are member functions, others are not. Member
functions can be called on temporary objects. boolalpha is handled by a
member function which returns std::istream&. That std::istream& can than
be accepted by both member and non-member operator>> functions.

#include<iostream>
#include<sstream>
#include<string>

using namespace std;

int main()
{
     string a("1234");
     // string b;
     int b;
     stringstream(a)>> b;
     cout<< b<< endl;
}

If we change the data type of b to int, the code works fine but not
with b as string. Why?


Because extracting into an integer is handled by a member function of
std::istream base class of std::stringstream.

Here is another trick to turn a temporary into an l-value, so that any
operator>> can work on a temporary stream object:

     template<class T>
     inline T& lvalue(T const& t) {
         return const_cast<T&>(t);
     }


Although this will be ill-formed because it requires the stream to have a
copy constructor. You could also use this trickery which i believe is safe:

template<typename T>
struct Lv {
  T t, &tr;
  Lv():t(), tr(t) {}
};

template<typename T>
T &lvalue(T &t = Lv<T>().tr) { return t; }

"lvalue<stringstream>()" now gives an lvalue of type stringstream, but this
doesn't allow passing arguments to its constructor :(

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