Re: simple reference "for each" question

From:
Cholo Lennon <chololennon@hotmail.com>
Newsgroups:
microsoft.public.vc.language
Date:
Thu, 04 Feb 2010 17:07:52 -0300
Message-ID:
<uQ78eVdpKHA.3664@TK2MSFTNGP04.phx.gbl>
NL wrote:

Hi,

try
for each(Foo &f in FooVector)

I tried that, it gives an error:
        error C2440: 'static_cast' : cannot convert from 'const Foo' to 'Foo
&'- Hide quoted text -

Sorry. I use the boost library and the code would look like

BOOST_FOREACH( Foo &f, FooVector )


I guess I'll switch over to the boost macro, since I'm already using
other boost stuff in the project. I was leaning toward the MS version
of for,each,in since it looks more elegant, but I guess it's limited
to "read-only".
Also the lack of thorough documentation on it leads me to think it may
be somewhat temporary.


You can use a const reference to avoid copies:

struct Foo {
  int a;
}

vector<Foo> FooVector;

for each(const Foo& f in FooVector )
{
    ...
}

AFAIK using const_cast should work in this case:

for each(const Foo& f in FooVector )
{
    const_cast<Foo&>(f).a = some_new_value;
}

A general solution could be:

template<typename T>
class noconst_ref_ptr
{
   T* m_ptr;

public:
   noconst_ref_ptr(const T& ref) : m_ptr(const_cast<T*>(&ref))
   {
   }

   T* operator->()
   {
     return m_ptr;
   }
};

....

for each(noconst_ref_ptr<Foo> f in FooVector )
{
    f->a = some_new_value;
}

At your own risk, or use BOOSR_FOREACH, std::for_each or for :-)

Regards

--
Cholo Lennon
Bs.As.
ARG

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