Re: reference to a pointer

From:
"io_x" <a@b.c.invalid>
Newsgroups:
comp.lang.c++
Date:
Sat, 30 Apr 2011 09:07:49 +0200
Message-ID:
<4dbbb50c$0$18249$4fafbaef@reader2.news.tin.it>
"graham" <gjw369@gmail.com> ha scritto nel messaggio
news:886df2af-6dbc-46e5-bc0f-7346c7c9e638@y31g2000vbp.googlegroups.com...

Hi,

I need to initialise a reference to a pointer. I'm a client of a
function that requires it.

Can you tell me how I can shorten the initalisation of totoToRef
below? I'm obviously going the long way about it.

void mymethod(toto& totoRef)
{

  toto* ptr = &totoRef;
  toto*& totoRefToPointer = ptr;

}

thanks and have a nice weekend.


where is the problem?
possible i not understand, but what would be the reason
to use "type*&" in some code? [i could admit not undestand
the meaning of that too]

the reference has for me the practical use of make one distinction:
the args the function change [use pointers] the args the function
not change [use reference] even if the language not guarantee that
i can guarantee that for the code i write.

#include <stdio.h>
#include <stdlib.h>

unsigned *totoRefToPointer;

/* for me this is a function that
  use totoRef and its pointer but should not change
 what the pointer point to */
void mymethod(unsigned& totoRef)
{totoRefToPointer=&totoRef;}

int main(void)
{unsigned x, y, z;

 mymethod(x);
 printf("%x %x\n", &x, totoRefToPointer);
 return 0;
}

...

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