Re: Template argument as rvalue reference

From:
SG <sgesemann@gmail.invalid>
Newsgroups:
comp.lang.c++
Date:
Fri, 26 Oct 2012 15:29:28 +0200
Message-ID:
<k6e37m$lda$1@news.albasani.net>
Am 26.10.2012 15:19, schrieb SG:

Am 26.10.2012 13:20, schrieb Juha Nieminen:

SG <sgesemann@gmail.invalid> wrote:

No, reference collapsing is always applicable. It is not restricted to
the case of templates.


I think it is.


Then you are wrong. Or perhaps you have a different idea about what
"reference collapsing" means.

If you have a non-templated rvalue reference parameter,
you can't give it an lvalue. You'll get a compile error.


What is an "rvalue reference parameter"?

    typedef int& foo;

    void bar(foo&& x);

    void test() {
        int a = 23;
        bar(a); // actually works
    }

Is x of bar an rvalue reference parameter? Well, it looks like one. But
it is not. Due to reference collapsing x is actually an lvalue
reference.


Let me stress that this reference collapsing has nothing to do with the
function call or the lvalue 'a' for that matter. Reference collapsing
applies because I wrote "foo&&" where foo is already a reference. The
reference collapsing rules turn foo&& into an lvalue reference as well,
because "lvalue references win", or, to put it differently: & + && = &.

Cheers!
SG

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