Re: Linkage of namespace scope reference

From:
johnchx2@yahoo.com
Newsgroups:
comp.std.c++
Date:
Tue, 13 Jun 2006 11:51:06 CST
Message-ID:
<1150213271.216845.40180@c74g2000cwc.googlegroups.com>
"Alf P. Steinbach" wrote:

* johnchx2@yahoo.com:

The extern keyword doesn't change whether a definition requires an
initializer;


True, because a reference definition always requires an initializer.

it only changes whether a declaration without an
initializer is also an (ill-formed) definition.


Typo? Sorry, I can't parse that.


Yeah...it makes my eyes cross too. But it says what I mean. For
instance:

  T& t;

is a well-formed declaration AND an ill-formed definition. But:

  extern T& t;

is a well-formed declaration that is NOT a definition.

So the presence or absence of extern only affects whether the
well-formed declaration is also an ill-formed definition.

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