Re: The use of const reference instear of getter

From:
=?UTF-8?B?RXJpayBXaWtzdHLDtm0=?= <Erik-wikstrom@telia.com>
Newsgroups:
comp.lang.c++
Date:
Mon, 04 Aug 2008 14:12:31 GMT
Message-ID:
<j7Elk.1382$U5.920@newsb.telia.net>
On 2008-08-04 15:54, Pascal J. Bourguignon wrote:

Erik Wikstr??m <Erik-wikstrom@telia.com> writes:

On 2008-08-04 13:42, Pascal J. Bourguignon wrote:

Turin <omar.hamidi@gmail.com> writes:

Dear all;

As far as I understand the idea behind getter methods, it is used to
make sure that private memers of a class is returned appropriately to
the calling object.

However, if all I am interested in when making a member private is to
disallow the modification of the value of that member (read-only
member), then how about doing the following:
[...]
I would like to know the opinion of C++ experts on this and if there
are any side-effects of this.
Also from the perferformance point of view, isn't using this mor
effecient than using a getter?

Looking forwards to hearing your opinions.

class A {
  public :
    const int& ref_to_priv_member;


Instead, do this:

      inline int ref_to_priv_member(void) const { return private_member; }


Nitpick:
inline is superfluous since the function is defined in the class
definition, and in C++ we usually write foo() and not foo(void), the
latter is considered bad style.


Why?

Is it because it reminds of the C ancestry?

Since I learned C first, I'm always afraid that with foo() it would
accept any number of arguments...


Well, for one it is inconsistent. If I write foo(bar) it means that foo
takes one argument of type bar, regardless if bar = void or not (in
other words foo(void) means foo takes one argument of type void). So for
me that means that the only way to call foo would be to somehow supply
an argument of type void.

--
Erik Wikstr??m

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