Re: why creating pointer to reference member is illegal?

From:
"Daniel T." <daniel_t@earthlink.net>
Newsgroups:
comp.lang.c++.moderated
Date:
Tue, 10 Mar 2009 18:07:17 CST
Message-ID:
<daniel_t-57A816.07083810032009@earthlink.vsrv-sjc.supernews.net>
blargg.ei3@gishpuppy.com (blargg) wrote:

fabio.lombardelli wrote:

can please somebody explain me why poiter to reference member are
illegal?
I'll show an example:

struct Test
{
        Test(int& ref_): ref(ref_) {}
        int& ref;
};

int main()
{
        int& Test::* ptom = &Test::ref;
}


Amazingly, none of the replies answered your question, because your
question looks like a much more common question. They answered the
following question:

     int main()
     {
         int i;
         Test t( &i );
         int&* p = &t.ref; // why can't I do this?
     }

Now that the wrong question is out of the way, perhaps we can now address
your question of why one can't take a pointer to MEMBER (not object) where
the member is a reference. Just as a refresher, this takes a pointer to
member for a NON-reference type:

     typedef int T; // why doesn't this work if changed to int&?

     struct X { T i; };

     void example( X& x )
     {
         T X::*mptr = &X::i; // get pointer to member
         x.*mptr = 123; // now dereference it on an object
     }

Why can't we do the same thing when i is of type int&?


For the same reason this doesn't work.

      typedef int& T;

      void example( T x )
      {
          T* p = &x; // get pointer to member
      }

And neither works for the exact reason I said earlier, you can only take
pointers to objects and functions... A reference is neither an object or
a function.

If you want to get deeper into the question, the next logical thing to
ask would be, why have a member reference in the first place? References
were not designed to be member variables.

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