Re: Reference to myself compiles... and crashes.

From:
=?windows-1252?Q?Daniel_Kr=FCgler?= <daniel.kruegler@googlemail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Tue, 6 Sep 2011 20:59:48 -0700 (PDT)
Message-ID:
<j45t6o$pdn$1@dont-email.me>
Am 06.09.2011 21:33, schrieb Francis Glassborow:

On 06/09/2011 07:45, Daniel Kr?gler wrote:

Am 06.09.2011 00:20, schrieb Javier Jimenez:

The example code bellow compiles in gcc, and produces a core dump.
When I noticed the error ( int& i = i; ), I would expected two
possible compiler behaviours:
- it does not compile.


There is currently a still open core issue related to this kind of
errors, see

http://www.open-std.org/jtc1/sc22/wg21/docs/cwg_active.html#504


No, that is a different issue and deals with:

type t=t;


Take a second look, Francis: Both the issue title and the discussion
talk about initialization of references.

No, this does not happen. A variable declaration introduces a name that
is immediately available in the initializer.


However the name being declared is NOT a variable. References are not
variables.


They are variables, this was one of the C++11 changes, see Clause 3 p6:

"A variable is introduced by the declaration of a reference other than a
non-static data member or of an object. The variable?s name denotes the
reference or object."

That cam as a bit of a surprise when I discovered it.
Variable and reference names are disjoint sets.


No longer any more!

There exist reasonable

examples where this can be useful, e.g.

void* p = &p;


Yes but that is taking an address, it is not a reference. The two cases
are different.


Yes, I agree that this was a bad example.

Greetings from Bremen,

- Daniel Kr?gler

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