Re: Taking a reference to a temporary: why illegal

From:
SG <s.gesemann@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Thu, 7 Mar 2013 03:24:24 -0800 (PST)
Message-ID:
<1613b6ae-b880-4cbd-8118-741da6400888@m4g2000vbo.googlegroups.com>
On Mar 7, 1:53 am, Chris Stankevitz wrote:

Is there a good reason that the code below is illegal?


Yes.

  void PrintValues(std::istream& Stream)
  {
    std::string String;
    while (Stream >> String) {
      std::cout << String << std::endl;
    }
  }

  int main()
  {
    PrintValues(std::istringstream("Hello, world!"));
    return 0;
  }


Though, I wonder that the "right" way to do this is. And I guess it
depends on how you look at it. My first thought that came up was to
add an overload

   inline void PrintValues(std::istream&& Stream)
   { PrintValues(Stream); }

My second thaught was to only provide a function taking an rvalue
reference. That would force people to use std::move in case of a named
stream:

   int main()
   {
     std::istringstream iss ("Hello");
     // #1
     PrintValues(std::move(iss));
     // #2
     PrintValues(std::istringstream("world!"));
   }

What I like about this is that due to std::move it's more obvious to
the reader that the state of iss at #2 will probably not be the same
as before at #1. That's something one might not expect of a function
with an innocent name like "PrintValues".

SG

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