Re: Taking a reference to a temporary: why illegal

SG <>
Thu, 7 Mar 2013 03:24:24 -0800 (PST)
On Mar 7, 1:53 am, Chris Stankevitz wrote:

Is there a good reason that the code below is illegal?


  void PrintValues(std::istream& Stream)
    std::string String;
    while (Stream >> String) {
      std::cout << String << std::endl;

  int main()
    PrintValues(std::istringstream("Hello, world!"));
    return 0;

Though, I wonder that the "right" way to do this is. And I guess it
depends on how you look at it. My first thought that came up was to
add an overload

   inline void PrintValues(std::istream&& Stream)
   { PrintValues(Stream); }

My second thaught was to only provide a function taking an rvalue
reference. That would force people to use std::move in case of a named

   int main()
     std::istringstream iss ("Hello");
     // #1
     // #2

What I like about this is that due to std::move it's more obvious to
the reader that the state of iss at #2 will probably not be the same
as before at #1. That's something one might not expect of a function
with an innocent name like "PrintValues".


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