Re: vector<vector<double> > & segmentation fault

utab wrote:


Consider

std::vector<Something> vec;

vec[0].doSomthing();

Which is pretty much what you have, with Something being a
vector<double> and doSomthing() being push_back().

Constructing a vector without a size does not initialise anything, it
might preallocate some memory, but that's it.

If you construct a vector with a size, size elements are default
constructed, giving you a vector of size default objects to use.

Same with resize (but not reserve).

You could have written:

for(sz=0;sz!=SIZE;++sz)
{
  field_values.push_back(vector<double>());
  field_values[sz].push_back(d);
}

Or

vector<vector<double> > field_values;
vector<vector<double> >::size_type SIZE=3;
vector<vector<double> >::size_type sz(SIZE);

--
Ian Collins.